This sliding-piece puzzle is a ball with three intersecting rings of moving pieces which divide the ball into eights. There are 12 square shaped pieces each ring, making 30 pieces in all because there are 6 places where the rings intersect. There is no space so the pieces do not move singly. Instead, all 12 pieces of a ring are shifted as one.

Note that the pieces come in inseparable antipodal pairs; pieces on opposite sides of the puzzle will always stay that way. Solving a piece on one side will automatically solve the piece on the other.

There are several versions of this puzzle, which differ only in the colour scheme. The Hungarian Globe (also known as Varázs Gömb, Globus Gömb, or Földgömb) simply has a map of the earth on it, like a proper globe. The Equator version of that puzzle has a simple colour scheme. Four quarters of the puzzle have a different colour. Thus the pieces at the poles have 4 colours, the pieces on the vertical rings have two, the remaining pieces only one. The Hungarian Globe and the Equator are both made of plastic with tin metal shells covering all the pieces, which makes it feel quite cool and solid. The I.Q. Ball, shown in the third picture, has six sets of 5 tiles. Each set has one colour, some with different symbols.

This puzzle should not be confused with the Massage Ball 2 which not only has a different colour scheme, it also allows two halves of the ball to rotate with respect to each other. Another related puzzle is the Mozaika where two halves on any of the three axes can rotate.

The Equator and Hungarian Globe were invented by Ferenc Molnár. Its original patent is HU 186,541, and the equivalent British patent GB 2,088,728 was published on 16 June 1982.

The I.Q. Ball was invented by Ming-Zen Liu and its US patent US 5,114,148 was published on 19 May 1982.

Let's consider the Hungarian Globe first. There are 15 pairs of pieces,
which can be placed in a position in 8 ways, giving a maximum of
15!·8^{15} positions. This limit is not reached because:

- No pair can be twisted a quarter turn in isolation (2)
- The parity of the tile permutation is the same as the parity of the tile pair permutation (2)

This leaves 15!·8^{15}/4 = 11,502,425,383,685,056,364,544,000 or
about 1.1·10^{25} positions. Note that the second constraint arises
from the fact that moving a ring one tile is an odd permutation on the 12
tiles and also an odd permutation on the 6 tile pairs. This means it is
impossible for example to swap two antipodal tiles without moving anything
else (though on the Equator puzzle that situation does occur because that
has identical tile pairs).

The Equator is simpler. Here the limit of 15!·8^{15} is not
reached because:

- Four pairs are monochrome so orientation does not matter (4
^{4}) - There are several indistinguishable pairs (2!·2!·5!·5!)

This leaves 15!/(2!·2!·5!·5!) · 8^{11}·2^{4} = 3,120,232,580,209,704,960
or 3.1·10^{18} positions.

The equatorial ring is moved Left or Right, denoted by L and R. The vertical ring going through the front goes Up or Down, denoted by U and D, while the other one goes Clockwise or Anti-clockwise, denoted by C and A. These letters are followed by a number indicating how many squares to move, so R3 means rotating the equator to the right a quarter turn.

**Phase 1:** Solve the front vertical ring (except pole/equator pieces).

- First find a piece that is to be placed on the front vertical ring (a two-coloured piece on the Equator puzzle). If the piece lies on the other vertical ring, then turn it (C or A) to the equator.
- Hold the puzzle so that the destination of the piece is one of the two places between the front and the top (north pole). Turn the equator (L or R) until the piece is at the front.
- There are 8 possibilities, depending on the orientation of the piece,
and whether it is to move up one or two squares.
Twist needed Up 1 square Up 2 squares None R1 D1 L1 U1 R1 D2 L1 U2 Clockwise L3 U2 C3 D2 L3 U1 C3 D1 Half turn R1 U5 R5 D5 R1 U4 R5 D4 Anti-clockwise R3 U2 A3 D2 R3 U1 A3 D1 - Repeat steps a-d until the ring is solved.

**Phase 2:** Solve the other vertical ring.

This is done exactly the same way as the first vertical ring. Rotate the whole
puzzle left or right a quarter turn, and repeat Phase 1. Afterwards
the first ring will not have been disturbed except that it may have been
rotated by a quarter or a half turn. Simply re-align it when you have
solved the second ring.

**Phase 3:** Solve the poles.

- If the North and South pole pieces are already at the pole positions but not correctly oriented, then bring them to the equator by D3 R1 U3.
- Rotate the equator to bring the North pole piece to the front.
- Now place it on the pole by using a method similar to phase 1:
Twist needed None R1 D3 L1 U3 Clockwise A3 L3 C3 Half turn R1 U3 R5 D3 Anti-clockwise C3 R3 A3

**Phase 4:** Orient (most of) the equatorial pieces.

In this phase the actual position of the pieces on the equator is ignored.

- If possible, find any two pieces on the equator (which are NOT an antipodal pair and) which are not in the correct orientation and both need to be twisted the same amount. Note that on the Equator puzzle, you can choose a monochrome piece as one of the two pieces if necessary.
- Turn the equator to bring one of the two twisted pieces to the front.
- Do one of the following sequences to twist the pieces:
Clockwise U3 R3 C3 R? L3 A3 L3 D3 Half turn U6 R? D6 Anti-clockwise U3 L3 A3 R? R3 C3 R3 D3 - Repeat steps a-c as often as possible.
- On the Equator puzzle, all pieces will now be correctly oriented because of the
monochrome pieces. On the Hungarian Globe you may still be left with one antipodal
pair that needs a half turn. To rectify this, use the first or third sequence above
to twist the pair a quarter turn, together with any other pair. You now have two
pairs which need a quarter turn, so you can again use the first or third sequence
to twist those two pairs correctly.

Alternatively, turn the tile to the front and do the sequence:

C3 D3 A3 U3 L3 U3 R3 C3 D3 A3 L3 A3 R3 C3

Note that this does not disturb any other pieces.

**Phase 5:** Position the equatorial pieces.

The phase is actually quite easy, but hard to explain.

- The tile at the front will be used as a reference point, and one by one matching tiles will be placed alongside it until (most of) the equatorial ring is solved. Call this front tile, tile f.
- Find the tile belonging to the right of the front tile. Call this tile r.
- Turn the equator to bring r to the front, and do U1 to lift it out of the equator.
- Turn the equator to bring f to the front, and do L1 D1. This brings down tile r next to tile f, so that they match. The tile below the front will be incorrect, but that will be corrected later.
- You will now essentially keep repeating steps a-d, lifting up pieces up from one place and dropping them elsewhere in the equator, at the correct position relative to the previously moved tiles. Continue until the equator is (nearly) solved.
- If it is not solved, then only one antipodal pair on the equator is incorrect, as well
as the tile just below the front and its antipode. Examine that tile below the front,
find the position in the equator where it should be and turn that to the front.
The following simple sequence should now solve the puzzle:

R1 U1 R1 D1 R1 U1 R1 D1 R1 U1 R1 D1.

Note how each tile on the equator is removed and placed back one tile further.